pyspark.RDD.sortByKey¶
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RDD.sortByKey(ascending=True, numPartitions=None, keyfunc=<function RDD.<lambda>>)[source]¶ Sorts this RDD, which is assumed to consist of (key, value) pairs.
Examples
>>> tmp = [('a', 1), ('b', 2), ('1', 3), ('d', 4), ('2', 5)] >>> sc.parallelize(tmp).sortByKey().first() ('1', 3) >>> sc.parallelize(tmp).sortByKey(True, 1).collect() [('1', 3), ('2', 5), ('a', 1), ('b', 2), ('d', 4)] >>> sc.parallelize(tmp).sortByKey(True, 2).collect() [('1', 3), ('2', 5), ('a', 1), ('b', 2), ('d', 4)] >>> tmp2 = [('Mary', 1), ('had', 2), ('a', 3), ('little', 4), ('lamb', 5)] >>> tmp2.extend([('whose', 6), ('fleece', 7), ('was', 8), ('white', 9)]) >>> sc.parallelize(tmp2).sortByKey(True, 3, keyfunc=lambda k: k.lower()).collect() [('a', 3), ('fleece', 7), ('had', 2), ('lamb', 5),...('white', 9), ('whose', 6)]